36x^2-73x-18=0

Solution for 36x^2-73x-18=0 equation:

36x^2-73x-18=0

a = 36; b = -73; c = -18;
Δ = b2-4ac
Δ = -732-4·36·(-18)
Δ = 7921
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7921}=89$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-73)-89}{2*36}=\frac{-16}{72}
=-2/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-73)+89}{2*36}=\frac{162}{72}
=2+1/4
$